This sample shows a macro version and the data step version that can be used to find the nth business day of a given month and year.
This example uses the INTNX function to increment the date, time, or datetime value by a given interval or intervals.
http://support.sas.com/onlinedoc/913/getDoc/en/lrdict.hlp/a000212700.htm
This macro is a modified version of the Source: http://support.sas.com/kb/37/632.html
/* This code creates the macro variable DAY that is the nth day of the month. The macro variable is in the SAS date format
*/
%macro test1(checkday,month,year);
%global day;
%let date=%str(%'01)%upcase(%substr(&month,1,3))&year%str(%'d);
%put date=&date;
%let n=0;
%do %until(&nthday=&checkday);
/* create a variable whose value is the first day of the month*/
%let begin_month=%sysfunc(intnx(month,&date,0,B));
/* increment the date by 1 day at a time*/
%let day=%sysfunc(intnx(day,&begin_month,&n));
/* determine the day of the week*/
%let weekday=%sysfunc(weekday(&day));
/* if the day of the week is not Saturday or Sunday then increment
nthday plus 1*/
%if &weekday ne 7 and &weekday ne 1 %then %let nthday=%eval(&nthday+1);
%let n=%eval(&n+1);
%end;
/* checks the DAY macro variable by writing it to the log in the DATE9.
format*/
%put %sysfunc(putn(&day,date9.));
%mend;
%test1(5,SEP,2010)
%macro test2(checkday,month,year););
%global day;
data test;
date=input(compress('01'||substr("&month",1,3)||&year),date9.);
put date=;
nthday=0;
n=0;
do until(nthday=&checkday);
begin_month=intnx('month',date,0,'B');
day=intnx('day',begin_month,n);
weekday=weekday(day);
if weekday ne 7 and weekday ne 1 then nthday=nthday+1;
n+1;
end;
drop begin_month weekday date n;
run;
proc print;
format day date9.;
run;
%mend;
%test2(8,april,2010)
